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A Light Ray Goes Through Two Thick Rectangular Slabs of Glass,each

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A light ray goes through two thick rectangular slabs of glass,each of the same uniform thickness.The first slab has index of refraction n1 and the second n2.If n1 < n2.How does the original angle of incidence θ\theta i into the first slab compare to the final angle of refraction θ\theta f where the ray leaves the second slab going back into air?  A light ray goes through two thick rectangular slabs of glass,each of the same uniform thickness.The first slab has index of refraction n<sub>1</sub> and the second n<sub>2</sub>.If n<sub>1</sub> < n<sub>2</sub>.How does the original angle of incidence  \theta <sub>i</sub> into the first slab compare to the final angle of refraction  \theta <sub>f</sub> where the ray leaves the second slab going back into air?   A)   \theta <sub>i</sub> >  \theta <sub>f</sub> B)   \theta <sub>i</sub> <  \theta <sub>f</sub> C)   \theta <sub>i</sub> =  \theta <sub>f</sub> D)   \theta <sub>i</sub> = (n<sub>1</sub>/n<sub>2</sub>)  \theta <sub>f</sub> E)  more information is needed


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