The Mean Free Path of a Molecule Is 2 $\times$ 10^-7 M in an Ideal Gas at Standard Temperature and 10^-7

question 22

Multiple Choice

The mean free path of a molecule is 2.25 $\times$ 10^-7 m in an ideal gas at standard temperature and pressure.What is the mean free path when the pressure of the gas is doubled and the temperature is tripled?

• A) 0.75 \(\times\) 10^-7m
• B) 1.13 \(\times\) 10^-7m
• C) 2.25 \(\times\) 10^-7m
• D) 3.38 \(\times\) 10^-7m
• E) 3.75 \(\times\) 10^-7m

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