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A Cable Is 5 ×\times 1010 N/m2

question 86

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A cable is 5.00 m long and has a diameter of 1.50 mm.The tensile modulus of the cable is 2.50 ×\times 1010 N/m2.A force is applied to the end of the cable and the cable stretches by 3.00 mm.What is the applied force?


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