The Number of Ways to Arrange X Successes Among N $\frac { n ! } { x ! ( n - x ) ! }$

question 95

Multiple Choice

The number of ways to arrange x successes among n trials is equal to

• A) \(\frac { n ! } { x ! ( n - x ) ! }\)
• B) \(\frac { n ! } { ( n - x ) ! }\)
• C) \(n / x\)
• D) \(n ! /x! \)

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