Using the Following Probability Distribution Table of the Random Variable$\begin{array} { c c }
\mathrm { X } & \mathrm { P } ( \mathrm { X } ) \
0 & 5 / 15 \
1 & 4 / 15 \
2 & 1 / 15 \
3 &
\end{array}$

Question

Using the Following Probability Distribution Table of the Random Variable$\begin{array} { c c } 
\mathrm { X } & \mathrm { P } ( \mathrm { X } ) \
0 & 5 / 15 \
1 & 4 / 15 \
2 & 1 / 15 \
3 &
\end{array}$

Examlex · Accepted Answer

The Answer of Using the Following Probability Distribution Table of the Random Variable$\begin{array} { c c } 
\mathrm { X } & \mathrm { P } ( \mathrm { X } ) \
0 & 5 / 15 \
1 & 4 / 15 \
2 & 1 / 15 \
3 &
\end{array}$

Using the Following Probability Distribution Table of the Random Variable $\begin{array} { c c } \mathrm { X } & \mathrm { P } ( \mathrm { X } ) \\0 & 5 / 15 \\1 & 4 / 15 \\2 & 1 / 15 \\3 &\end{array}$

Definitions:

Using the Following Probability Distribution Table of the Random Variable XP(X)05/1514/1521/153\begin{array} { c c } \mathrm { X } & \mathrm { P } ( \mathrm { X } ) \\0 & 5 / 15 \\1 & 4 / 15 \\2 & 1 / 15 \\3 &\end{array}X0123​P(X)5/154/151/15​

Definitions:

Using the Following Probability Distribution Table of the Random Variable $\begin{array} { c c } \mathrm { X } & \mathrm { P } ( \mathrm { X } ) \\0 & 5 / 15 \\1 & 4 / 15 \\2 & 1 / 15 \\3 &\end{array}$