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Determine How Much Energy Is Released When Polonium-210 Decays According 210Po4He+206 Pb{ }^{210} \mathrm{Po} \rightarrow{ }^{4} \mathrm{He}+{ }^{206} \mathrm{~Pb}

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Determine how much energy is released when polonium-210 decays according to 210Po4He+206 Pb{ }^{210} \mathrm{Po} \rightarrow{ }^{4} \mathrm{He}+{ }^{206} \mathrm{~Pb} . [Atomic masses: polonium-210 = 209.982857 amu; helium-4 = 4.002603 amu; lead-206 = 205.974449 amu]


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