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For the Reaction SbCl5(g) \leftrightharpoons SbCl3(g) + Cl2(g) Δ\Delta G \circ f (SbCl5) = -334

question 78

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For the reaction SbCl5(g) \leftrightharpoons SbCl3(g) + Cl2(g),
Δ\Delta G \circ f (SbCl5) = -334.34 kJ/mol
Δ\Delta G \circ f (SbCl3) = -301.25 kJ/mol
Δ\Delta H \circ f (SbCl5) = -394.34 kJ/mol
Δ\Delta H \circ f (SbCl3) = -313.80 kJ/mol
This reaction proceeds spontaneously at 298 K and 1 atm pressure.


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