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For the reaction CuS(s) + H2(g) H2S(g) + Cu(s) ,
G f (CuS) = -53.6 kJ/mol
G f (H2S) = -33.6 kJ/mol
H f (CuS) = -53.1 kJ/mol
H f (H2S) = - 20.6 kJ/mol
Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K.
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