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For the Reaction CuS(s) + H2(g) \leftrightharpoons H2S(g) + Cu(s) Δ\Delta G \circ

question 114

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For the reaction CuS(s) + H2(g) \leftrightharpoons H2S(g) + Cu(s) ,
Δ\Delta G \circ f (CuS) = -53.6 kJ/mol
Δ\Delta G \circ f (H2S) = -33.6 kJ/mol
Δ\Delta H \circ f (CuS) = -53.1 kJ/mol
Δ\Delta H \circ f (H2S) = -20.6 kJ/mol
Calculate Δ\Delta G at 798 K and 1 atm pressure (assume Δ\Delta S \circ and Δ\Delta H \circ do not change with temperature) .


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