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How Much Energy (Heat) Is Required to Convert 25 \circ C to H2O(g) at 115

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How much energy (heat) is required to convert 25.5 g of H2O(l) at 35.0 \circ C to H2O(g) at 115.0 \circ C

specific heat of ice: 2.09 J/gCΔHfus=6.02 kJ/mol \quad 2.09 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C} \quad \Delta \mathrm{H}_{\mathrm{fus}}=6.02 \mathrm{~kJ} / \mathrm{mol}
specific heat of water: 4.18 J/gCΔHvap=40.7 kJ/mo 4.18 \mathrm{~J} / \mathrm{g}{ \cdot}^{\circ} \mathrm{C} \quad \Delta \mathrm{H}_{\mathrm{vap}}=40.7 \mathrm{~kJ} / \mathrm{mo} .
specific hast of steam: 1.84 J/gC 1.84 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}


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