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Calculate the Standard Enthalpy Change for the Reaction 2C8H18(l) \rarr 16CO(g) + 18H2O(l)

question 9

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Calculate the standard enthalpy change for the reaction 2C8H18(l) + 17O2(g) \rarr 16CO(g) + 18H2O(l) .Given 2C8H18(l) +25O2(g) 16CO2(g) +18H2O(l) ΔH=11,020 kJ/mol2CO(g) +O2(g) 2CO2(g) ΔH=566.0 kJ/mol\begin{array}{ll}2 \mathrm{C}_{8} \mathrm{H}_{18}(\mathrm{l}) +25 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 16 \mathrm{CO}_{2}(\mathrm{g}) +18 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) & \Delta \mathrm{H}^{\circ}=-11,020 \mathrm{~kJ} / \mathrm{mol} \\2 \mathrm{CO}(\mathrm{g}) +\mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{CO}_{2}(\mathrm{g}) & \Delta \mathrm{H}^{\circ}=-566.0 \mathrm{~kJ} / \mathrm{mol}\end{array}


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