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Calculate the heat released (kJ) in the reaction of 3.50 g of acetylene (C2H2) and excess hydrogen gas to form ethane gas: C2H2(g) + 2H2(g) C2H6(g)
Given:
2C2H2(g) + 5O2(g) 4CO2(g) + 2H2O(g) H = -2320 kJ/mol
2C2H6(g) + 7O2(g) 4CO2(g) + 6H2O(g) H = -3040 kJ/mol
2H2(g) + O2(g) 2H2O(g) H = -572 kJ/mol
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