For the Reaction SbCl₅(g) $\rarr$ SbCl₃(g)+ Cl₂(g) $\Delta$ G°_f (SbCl₅)= -334 $\Delta$ G°_f (SbCl₃)= -301

question 94

Short Answer

For the reaction SbCl₅(g) $\rarr$ SbCl₃(g)+ Cl₂(g),
$\Delta$ G°_f (SbCl₅)= -334.34 kJ/mol
$\Delta$ G°_f (SbCl₃)= -301.25 kJ/mol
$\Delta$ H°_f (SbCl₅)= -394.34 kJ/mol
$\Delta$ H°_f (SbCl₃)= -313.80 kJ/mol
Will this reaction proceed spontaneously at 298 K and 1 atm pressure?

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