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O2(g) + 4 H+(aq) + 4 e- → 2 H2O(l) E° = +1.23 V Pb2+(aq) + 2 e- → Pb(s) E° = -0.13 V
2 H2O(l) + 2 e- → H2(g) + 2 OH-(aq) E° = -0.83 V
Based on the half-reactions above,electrolysis of an aqueous solution of Pb(NO3) 2 is expected to produce.
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