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One step in the isolation of pure rhodium metal (Rh) is the precipitation of rhodium(III) hydroxide from a solution containing rhodium(III) sulfate according to the following balanced chemical equation:
Rh2(SO4) 3(aq) + 6NaOH(aq) → 2Rh(OH) 3(s) + 3Na2SO4(aq)
What is the theoretical yield of rhodium(III) hydroxide from the reaction of 0.540 g of rhodium(III) sulfate with 0.209 g of sodium hydroxide?
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