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What Is the Standard Enthalpy of Formation of Liquid Methylamine

question 68

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What is the standard enthalpy of formation of liquid methylamine (CH3NH2) ?
C(s) + O2(g) → CO2(g) ; ΔH° = -393.5 kJ
2H2O(l) → 2H2(g) + O2(g) ; ΔH° = 571.6 kJ What is the standard enthalpy of formation of liquid methylamine (CH<sub>3</sub>NH<sub>2</sub>) ? C(s) + O<sub>2</sub>(g) → CO<sub>2</sub>(g) ; ΔH° = -393.5 kJ 2H<sub>2</sub>O(l) → 2H<sub>2</sub>(g) + O<sub>2</sub>(g) ; ΔH° = 571.6 kJ   N<sub>2</sub>(g) + O<sub>2</sub>(g) → NO<sub>2</sub>(g) ; ΔH° = 33.10 kJ 4CH<sub>3</sub>NH<sub>2</sub>(l) + 13O<sub>2</sub>(g) → 4CO<sub>2</sub>(g) + 4NO<sub>2</sub>(g) + 10H<sub>2</sub>O(l) ; ΔH° = -4110.4 kJ A) +3899.2 kJ/mol B) -3899.2 kJ/mol C) -47.3 kJ/mol D) +47.3 kJ/mol E) +3178.4 kJ
N2(g) + O2(g) → NO2(g) ; ΔH° = 33.10 kJ
4CH3NH2(l) + 13O2(g) → 4CO2(g) + 4NO2(g) + 10H2O(l) ; ΔH° = -4110.4 kJ


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