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Given That O(g)+ E- → O-(g); ΔH = -142 KJ

question 117

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Given that
O(g) + e- → O-(g) ; ΔH = -142 kJ
O(g) + 2e- → O2-(g) ; ΔH = 702 kJ
The enthalpy change for the reaction represented by the equation
O-(g) + e- → O2-(g) is


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