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The Gas-Phase Decomposition of N2O5 Is a First-Order Process with a Rate

question 46

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The gas-phase decomposition of N2O5 is a first-order process with a rate constant of 1.50 × 10-3 s-1 at 55°C.The decomposition reaction is
N2O5(g) → 2NO2(g) + The gas-phase decomposition of N<sub>2</sub>O<sub>5</sub> is a first-order process with a rate constant of 1.50 × 10<sup>-3</sup> s<sup>-1</sup> at 55°C.The decomposition reaction is N<sub>2</sub>O<sub>5</sub>(g) → 2NO<sub>2</sub>(g) +   O<sub>2</sub>(g)  If 8.0 g of N<sub>2</sub>O<sub>5</sub> is placed in vessel 1 and 16.0 g of N<sub>2</sub>O<sub>5</sub> in vessel 2 and the vessels are at the same temperature (55°C) and the same pressure,how much time is required for half of the N<sub>2</sub>O<sub>5</sub> to decompose in each vessel? A) Vessel 1 requires the same amount of time as vessel 2. B) Vessel 1 requires twice as much time as vessel 2. C) Vessel 1 requires three times as much time as vessel 2. D) Vessel 1 requires four times as much time as vessel 2. E) Vessel 2 requires twice as much time as vessel 1.
O2(g)
If 8.0 g of N2O5 is placed in vessel 1 and 16.0 g of N2O5 in vessel 2 and the vessels are at the same temperature (55°C) and the same pressure,how much time is required for half of the N2O5 to decompose in each vessel?


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