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At 400 K,an Equilibrium Mixture of H2,I2,and HI Consists of 0.025

question 51

Multiple Choice

At 400 K,an equilibrium mixture of H2,I2,and HI consists of 0.025 mol H2,0.067 mol I2,and 0 mol HI in a 3.50-L flask.What is the value of Kp for the following equilibrium? (R = 0.0821 L ∙ atm/(K ∙ mol) )
2HI(g) At 400 K,an equilibrium mixture of H<sub>2</sub>,I<sub>2</sub>,and HI consists of 0.025 mol H<sub>2</sub>,0.067 mol I<sub>2</sub>,and 0 mol HI in a 3.50-L flask.What is the value of K<sub>p</sub> for the following equilibrium? (R = 0.0821 L ∙ atm/(K ∙ mol) )  2HI(g)   H<sub>2</sub>(g) + I<sub>2</sub>(g)  A) 0 B) 15 C) 2 D) 45 E) 3H2(g) + I2(g)


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