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What Is Kc for the Following Equilibrium? for Phosphoric Acid

question 48

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What is Kc for the following equilibrium? For phosphoric acid (H3PO4) ,Ka1 = 6.9 × 10-3,Ka2 = 6.2 × 10-8,and Ka3 = 4.8 × 10-13.
HPO42-(aq) + OH-(aq) What is K<sub>c</sub> for the following equilibrium? For phosphoric acid (H<sub>3</sub>PO<sub>4</sub>) ,Ka<sub>1</sub> = 6.9 × 10<sup>-3</sup>,Ka<sub>2</sub> = 6.2 × 10<sup>-8</sup>,and Ka<sub>3</sub> = 4.8 × 10<sup>-13</sup>. HPO<sub>4</sub><sup>2-</sup>(aq) + OH<sup>-</sup>(aq)    PO<sub>4</sub><sup>3-</sup>(aq) + H<sub>2</sub>O(l)  A) 7.3 × 10<sup>-16</sup> B) 6.4 × 10<sup>-23</sup> C) 491 D) 48 E) 2.3 × 10<sup>-35</sup>
PO43-(aq) + H2O(l)


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