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In order to determine the identity of a particular lanthanide metal (M) ,a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl3,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO3) 2 solution.The two half-reactions are as follows:
M(s) M3+(aq) + 3e- Cu2+(aq) + 2e-
Cu(s)
The potential measured across the cell is 2.70 V.What is the identity of the metal?
Reduction Half-Reaction
E° (V)
Cu2+(aq) + 2e- Cu(s) 0.34
Ce3+(aq) + 3e- Ce(s) -2.336
Tm3+(aq) + 3e- Tm(s) -2.319
Eu3+(aq) + 3e- Eu(s) -1.991
Gd3+(aq) + 3e- Gd(s) -2.279
Sm3+(aq) + 3e- Sm(s) -2.304
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