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In Order to Determine the Identity of a Particular Lanthanide

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In order to determine the identity of a particular lanthanide metal (M) ,a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl3,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO3) 2 solution.The two half-reactions are as follows:
M(s) In order to determine the identity of a particular lanthanide metal (M) ,a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>) <sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>3+</sup>(aq) + 3e<sup>-</sup> Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s)  The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V)  Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s) 0.34 Ce<sup>3+</sup>(aq) + 3e<sup>-</sup>  Ce(s) -2.336 Tm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Tm(s) -2.319 Eu<sup>3+</sup>(aq) + 3e<sup>-</sup>  Eu(s) -1.991 Gd<sup>3+</sup>(aq) + 3e<sup>-</sup>  Gd(s) -2.279 Sm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Sm(s) -2.304 A) Tm B) Gd C) Ce D) Eu E) SmM3+(aq) + 3e- Cu2+(aq) + 2e- In order to determine the identity of a particular lanthanide metal (M) ,a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>) <sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>3+</sup>(aq) + 3e<sup>-</sup> Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s)  The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V)  Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s) 0.34 Ce<sup>3+</sup>(aq) + 3e<sup>-</sup>  Ce(s) -2.336 Tm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Tm(s) -2.319 Eu<sup>3+</sup>(aq) + 3e<sup>-</sup>  Eu(s) -1.991 Gd<sup>3+</sup>(aq) + 3e<sup>-</sup>  Gd(s) -2.279 Sm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Sm(s) -2.304 A) Tm B) Gd C) Ce D) Eu E) SmCu(s)
The potential measured across the cell is 2.70 V.What is the identity of the metal?
Reduction Half-Reaction
E° (V)
Cu2+(aq) + 2e- In order to determine the identity of a particular lanthanide metal (M) ,a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>) <sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>3+</sup>(aq) + 3e<sup>-</sup> Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s)  The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V)  Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s) 0.34 Ce<sup>3+</sup>(aq) + 3e<sup>-</sup>  Ce(s) -2.336 Tm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Tm(s) -2.319 Eu<sup>3+</sup>(aq) + 3e<sup>-</sup>  Eu(s) -1.991 Gd<sup>3+</sup>(aq) + 3e<sup>-</sup>  Gd(s) -2.279 Sm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Sm(s) -2.304 A) Tm B) Gd C) Ce D) Eu E) SmCu(s) 0.34
Ce3+(aq) + 3e- In order to determine the identity of a particular lanthanide metal (M) ,a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>) <sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>3+</sup>(aq) + 3e<sup>-</sup> Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s)  The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V)  Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s) 0.34 Ce<sup>3+</sup>(aq) + 3e<sup>-</sup>  Ce(s) -2.336 Tm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Tm(s) -2.319 Eu<sup>3+</sup>(aq) + 3e<sup>-</sup>  Eu(s) -1.991 Gd<sup>3+</sup>(aq) + 3e<sup>-</sup>  Gd(s) -2.279 Sm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Sm(s) -2.304 A) Tm B) Gd C) Ce D) Eu E) SmCe(s) -2.336
Tm3+(aq) + 3e- In order to determine the identity of a particular lanthanide metal (M) ,a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>) <sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>3+</sup>(aq) + 3e<sup>-</sup> Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s)  The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V)  Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s) 0.34 Ce<sup>3+</sup>(aq) + 3e<sup>-</sup>  Ce(s) -2.336 Tm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Tm(s) -2.319 Eu<sup>3+</sup>(aq) + 3e<sup>-</sup>  Eu(s) -1.991 Gd<sup>3+</sup>(aq) + 3e<sup>-</sup>  Gd(s) -2.279 Sm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Sm(s) -2.304 A) Tm B) Gd C) Ce D) Eu E) SmTm(s) -2.319
Eu3+(aq) + 3e- In order to determine the identity of a particular lanthanide metal (M) ,a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>) <sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>3+</sup>(aq) + 3e<sup>-</sup> Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s)  The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V)  Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s) 0.34 Ce<sup>3+</sup>(aq) + 3e<sup>-</sup>  Ce(s) -2.336 Tm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Tm(s) -2.319 Eu<sup>3+</sup>(aq) + 3e<sup>-</sup>  Eu(s) -1.991 Gd<sup>3+</sup>(aq) + 3e<sup>-</sup>  Gd(s) -2.279 Sm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Sm(s) -2.304 A) Tm B) Gd C) Ce D) Eu E) SmEu(s) -1.991
Gd3+(aq) + 3e- In order to determine the identity of a particular lanthanide metal (M) ,a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>) <sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>3+</sup>(aq) + 3e<sup>-</sup> Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s)  The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V)  Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s) 0.34 Ce<sup>3+</sup>(aq) + 3e<sup>-</sup>  Ce(s) -2.336 Tm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Tm(s) -2.319 Eu<sup>3+</sup>(aq) + 3e<sup>-</sup>  Eu(s) -1.991 Gd<sup>3+</sup>(aq) + 3e<sup>-</sup>  Gd(s) -2.279 Sm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Sm(s) -2.304 A) Tm B) Gd C) Ce D) Eu E) SmGd(s) -2.279
Sm3+(aq) + 3e- In order to determine the identity of a particular lanthanide metal (M) ,a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>) <sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>3+</sup>(aq) + 3e<sup>-</sup> Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s)  The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V)  Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>  Cu(s) 0.34 Ce<sup>3+</sup>(aq) + 3e<sup>-</sup>  Ce(s) -2.336 Tm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Tm(s) -2.319 Eu<sup>3+</sup>(aq) + 3e<sup>-</sup>  Eu(s) -1.991 Gd<sup>3+</sup>(aq) + 3e<sup>-</sup>  Gd(s) -2.279 Sm<sup>3+</sup>(aq) + 3e<sup>-</sup>  Sm(s) -2.304 A) Tm B) Gd C) Ce D) Eu E) SmSm(s) -2.304


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