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A 3.0-m rod is pivoted about its left end.A force of 10 N is applied perpendicular to the rod at a distance of 1.2 m from the pivot causing a ccw torque,and a force of 5.2 N is applied at the end of the rod 3.0 m from the pivot.The 5.2-N force is at an angle of 30o to the rod and causes a cw torque.What is the net torque about the pivot? (Take ccw as positive. )
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