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I take 0.9 kg of ice and dump it into 0.9 kg of water and,when equilibrium is reached,I have 1.8 kg of ice at 0°C.The water was originally at 0°C.The specific heat of water = 1.00 kcal/kg⋅°C,the specific heat of ice = 0.50 kcal/kg⋅°C,and the latent heat of fusion of water is 80 kcal/kg.The original temperature of the ice was:
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