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The electric field in a cathode ray tube is supposed to accelerate electrons from 0 to 4.8 × 107 m/s in a distance of 5.00 cm.What electric field is required? (me = 9.11 × 10−31 kg and e = 1.60 × 10−19 C)
Q5: Consider the circuit shown in the figure.What
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Q12: The current in an electron beam in
Q14: A Van de Graaff generator has a
Q25: A uniform electric field,with a magnitude of
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Q54: Charge A and charge B are 3.12