The Solubility Product Constant of PbI₂(s)is 7

question 21

Multiple Choice

The solubility product constant of PbI₂(s) is 7.1 × 10^-9.How many moles of PbI₂ will precipitate if 250 mL of a 0.200 M solution of NaI(aq) are added to 150 mL of 0.100 M solution of Pb(NO₃) ₂(aq) ? You may neglect hydrolysis.

• A)0.050 mol
• B)1.3 × 10^-5 mol
• C)0.015 mol
• D)5.6 × 10^-3 mol
• E)0.040 mol

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