For the Following Voltaic Cell,determine the [Cl^-] When

question 90

Multiple Choice

For the following voltaic cell,determine the [Cl^-] when
= 0.500 atm,[Zn²⁺] = 1.77 × 10^-2 M,and E_cell = 2.250 V.The half-reactions at 25 °C are:
Cl₂(g) + 2 e^- → 2 Cl^-(aq) E° = +1.358 V
Zn²⁺(aq) + 2 e^- → Zn(s) E° = -0.763 V
Zn(s) ∣ Zn²⁺(aq) Cl^-(aq) ,Cl₂(g) ∣ Pt(s)

• A)5.48 × 10^-6 M
• B)2.32 × 10^-3 M
• C)0.0296 M
• D)0.0939 M
• E)0.0352 M

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