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Determine E°cell at 25 °C for the following reaction:
Pb2+(aq) + Cu(s) → Cu2+(aq) + Pb(s)
The half-reactions are:
Pb2+(aq) + 2 e- → Pb(s) E° = -0.125 V
Cu2+(aq) + 2 e- → Cu(s) E° = +0.337 V
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