When [Ni(NH₃)₄]²⁺ Is Treated with Concentrated HCl(aq),two Compounds Having the Same

question 22

Multiple Choice

When [Ni(NH₃) ₄]²⁺ is treated with concentrated HCl(aq) ,two compounds having the same formula,[Ni(NH₃) ₄Cl₂],designated I and II,are formed.Compound I can be converted to compound II by boiling it in dilute HCl(aq) .A solution of I reacts with oxalic acid,H₂C₂O₄,to form [Ni(NH₃) ₄(C₂O₄) ].Compound II does not react with oxalic acid.Compound II is:

• A)the cis isomer
• B)tetrahedral in shape
• C)the trans isomer
• D)the same as compound I
• E)octahedral in shape

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