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If the Probability Distribution of X Is XP(X)00.110.220.330.4\begin{array} { c c } \mathrm { X } & \mathrm { P } ( \mathrm { X } ) \\0 & 0.1 \\1 & 0.2 \\2 & 0.3 \\3 & 0.4\end{array}

question 75

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If the probability distribution of X is: XP(X)00.110.220.330.4\begin{array} { c c } \mathrm { X } & \mathrm { P } ( \mathrm { X } ) \\0 & 0.1 \\1 & 0.2 \\2 & 0.3 \\3 & 0.4\end{array}
-What is the variance of X?


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