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The Equilibrium Constant at 427°C for the Reaction N2(g)+ 3H2(g) Δ\Delta

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The equilibrium constant at 427°C for the reaction N2(g) + 3H2(g)  The equilibrium constant at 427°C for the reaction N<sub>2</sub>(g) + 3H<sub>2</sub>(g)    <sub> </sub> 2NH<sub>3</sub>(g) is K<sub>p</sub> = 9.4 × 10<sup>-5</sup>.Calculate the value of  \Delta G° for the reaction under these conditions. A) -33 kJ/mol B) -54 kJ/mol C) 54 kJ/mol D) 33 kJ/mol E) 1.3 J/mol 2NH3(g) is Kp = 9.4 × 10-5.Calculate the value of Δ\Delta G° for the reaction under these conditions.


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