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For the Reaction CuS(s)+ H2(g)
H2S(g) Δ\Delta

question 27

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For the reaction CuS(s)+ H2(g)  For the reaction CuS(s)+ H<sub>2</sub>(g)   <sub> </sub> <sub> </sub>H<sub>2</sub>S(g)+ Cu(s),  \Delta G°<sub>f</sub> (CuS)= -53.6 kJ/mol  \Delta G°<sub>f</sub> (H<sub>2</sub>S)= -33.6 kJ/mol  \Delta H°<sub>f</sub> (CuS)= -53.1 kJ/mol  \Delta H°<sub>f</sub> (H<sub>2</sub>S)= -20.6 kJ/mol Calculate  \Delta G at 798 K and 1 atm pressure (assume  \Delta S°<sub> </sub>and  \Delta H° do not change with temperature).
H2S(g)+ Cu(s),
Δ\Deltaf (CuS)= -53.6 kJ/mol
Δ\Deltaf (H2S)= -33.6 kJ/mol
Δ\Deltaf (CuS)= -53.1 kJ/mol
Δ\Deltaf (H2S)= -20.6 kJ/mol
Calculate Δ\Delta G at 798 K and 1 atm pressure (assume Δ\Delta and Δ\Delta H° do not change with temperature).


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