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Calculate the Energy Released in Joules When One Mole of Polonium-214

question 59

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Calculate the energy released in joules when one mole of polonium-214 decays according to the equation Calculate the energy released in joules when one mole of polonium-214 decays according to the equation   Po     Pb +   He. [Atomic masses: Pb-210 = 209.98284 amu, Po-214 = 213.99519 amu, He-4 = 4.00260 amu.] A) 8.78 × 10<sup>14</sup> J/mol B) 7.2 × 10<sup>14</sup> J/mol C) 8.78 × 10<sup>11</sup> J/mol D) -9.75 × 10<sup>-3</sup> J/mol E) 1.46 × 10<sup>-9</sup> J/mol Po Calculate the energy released in joules when one mole of polonium-214 decays according to the equation   Po     Pb +   He. [Atomic masses: Pb-210 = 209.98284 amu, Po-214 = 213.99519 amu, He-4 = 4.00260 amu.] A) 8.78 × 10<sup>14</sup> J/mol B) 7.2 × 10<sup>14</sup> J/mol C) 8.78 × 10<sup>11</sup> J/mol D) -9.75 × 10<sup>-3</sup> J/mol E) 1.46 × 10<sup>-9</sup> J/mol Calculate the energy released in joules when one mole of polonium-214 decays according to the equation   Po     Pb +   He. [Atomic masses: Pb-210 = 209.98284 amu, Po-214 = 213.99519 amu, He-4 = 4.00260 amu.] A) 8.78 × 10<sup>14</sup> J/mol B) 7.2 × 10<sup>14</sup> J/mol C) 8.78 × 10<sup>11</sup> J/mol D) -9.75 × 10<sup>-3</sup> J/mol E) 1.46 × 10<sup>-9</sup> J/mol Pb + Calculate the energy released in joules when one mole of polonium-214 decays according to the equation   Po     Pb +   He. [Atomic masses: Pb-210 = 209.98284 amu, Po-214 = 213.99519 amu, He-4 = 4.00260 amu.] A) 8.78 × 10<sup>14</sup> J/mol B) 7.2 × 10<sup>14</sup> J/mol C) 8.78 × 10<sup>11</sup> J/mol D) -9.75 × 10<sup>-3</sup> J/mol E) 1.46 × 10<sup>-9</sup> J/mol He. [Atomic masses: Pb-210 = 209.98284 amu, Po-214 = 213.99519 amu, He-4 = 4.00260 amu.]


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