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Octane (C8H18) undergoes combustion according to the following thermochemical equation: 2C8H18(l) + 25O2(g) 16CO2(g) + 18H2O(l)
H°rxn = -11,020 kJ/mol.
Given that H°f[CO2(g) ] = -393.5 kJ/mol and H°f[H2O(l) ] = -285.8 kJ/mol, calculate the standard enthalpy of formation of octane.
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