Using the Born-Haber Cycle, the ΔH_f° of KBr Is Equal

question 28

Multiple Choice

Using the Born-Haber cycle, the ΔH_f° of KBr is equal to __________.

• A)ΔH_f°[K (g)] + ΔH_f°[Br (g)] + I_l(K)+ E(Br)+ ΔH_lattice
• B)ΔH_f°[K (g)] - ΔH_f°[Br (g)] - I_l(K)- E(Br)- ΔH_lattice
• C)ΔH_f°[K (g)] - ΔH_f°[Br (g)] + I_l(K)- E(Br)+ ΔH_lattice
• D)ΔH_f°[K (g)] + ΔH_f°[Br (g)] - I_l - E(Br)+ ΔH_lattice
• E)ΔH_f°[K (g)] + ΔH_f°[Br (g)] + I_l(K)+ E(Br)- ΔH_lattice