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The Peroxydisulfate Ion (S2O82-)reacts with the Iodide Ion in Aqueous

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The peroxydisulfate ion (S2O82-) reacts with the iodide ion in aqueous solution via the reaction:
S2O82- (aq) + 3I- → 2SO4 (aq) + I3- (aq)
An aqueous solution containing 0.050 M of S2O82- ion and 0.072 M of I- is prepared, and the progress of the reaction followed by measuring [I-]. The data obtained is given in the table below. The peroxydisulfate ion (S<sub>2</sub>O<sub>8</sub><sup>2-</sup>) reacts with the iodide ion in aqueous solution via the reaction: S<sub>2</sub>O<sub>8</sub><sup>2-</sup> (aq)  + 3I<sup>-</sup> → 2SO<sub>4</sub> (aq) + I<sub>3</sub><sup>-</sup> (aq)  An aqueous solution containing 0.050 M of S<sub>2</sub>O<sub>8</sub><sup>2-</sup> ion and 0.072 M of I<sup>-</sup> is prepared, and the progress of the reaction followed by measuring [I<sup>-</sup>]. The data obtained is given in the table below.   -The average rate of disappearance of I<sup>-</sup> in the initial 400.0 s is ________ M/s. A) 6.00 B) 3.8 × 10<sup>-5</sup> C) 1.4 × 10<sup>-4</sup> D) 2.7 × 10<sup>4</sup> E) 3.2 × 10<sup>-4</sup>
-The average rate of disappearance of I- in the initial 400.0 s is ________ M/s.


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