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Calculate the energy change for the formation of LiCl(s) from its elements in their standard states and the following tabulated information: Li(s) + 1/2 Cl2(g) → LiCl(s) ?
Li+(g) + Cl-(g) → LiCl(s) -853 kJ/mol
Li(s) → Li(g) +159.4 kJ/mol
1/2 Cl2(g) → Cl(g) +121.7 kJ/mol
Cl(g) + e- → Cl-(g) -348.6 kJ/mol
Li(g) → Li+(g) + e- +520.2 kJ/mol
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