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Calculate the electron affinity for the formation of the hydride ion from the following information: H(g) + e- → H-(g) ?
1/2 H2(g) → H(g) +217.9 kJ/mol
Na(s) → Na(g) +107.3 kJ/mol
Na(g) → Na+(g) + e- +495.8 kJ/mol
Na(s) + 1/2 H2(g) → NaH(s) -60.0 kJ/mol
NaH(s) → Na+(g) + H-(g) +810.9 kJ/mol
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