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When 2.500 mol of CH4(g) reacts with excess Cl2(g) at constant pressure according to the chemical equation shown below,1770.kJ of heat are released.Calculate the value of ΔH for this reaction,as written. 2 CH4(g) + 3 Cl2(g) → 2 CHCl3(l) + 3 H2(g) ΔH = ?
Lbs. Of Tea
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Opportunity Cost
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