The Second-Order Reaction,2 Mn(CO)₅ → Mn₂(CO)₁₀ Has a Rate Constant

question 153

Multiple Choice

The second-order reaction,2 Mn(CO) ₅ → Mn₂(CO) ₁₀ has a rate constant equal to 3.0 × 10⁹ M^-1s^-1 at 25°C.If the initial concentration of Mn(CO) ₅ is 1.0 × 10^-5 M,how long will it take for 90.% of the reactant to disappear?

• A)3.3 × 10^-16 s
• B)3.7 × 10^-15 s
• C)3.0 × 10^-4 s
• D)3.0 × 10³ s

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