The Balanced Equation for the Solubility Equilibrium of Ba(OH)₂ Is

question 36

Multiple Choice

The balanced equation for the solubility equilibrium of Ba(OH) ₂ is shown below.What is the equilibrium constant expression for the K_sp of Ba(OH) ₂? Ba(OH) ₂(s) ⇌ Ba²⁺(aq) + 2 OH^-(aq)

• A)K_sp = {[Ba²⁺][OH^-]²}/{[Ba(OH)₂][H₂O]}
• B)K_sp = {[Ba²⁺][OH^-]²}/[Ba(OH)₂]
• C)K_sp = [Ba²⁺][OH^-]²
• D)K_sp = 1/{[Ba²⁺][OH^-]²}

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