Examlex

Solved

The Equilibrium Constant,K,for the Reaction 2HgO(s) 2Hg(l)+ O2(g)

question 70

Multiple Choice

The equilibrium constant,K,for the reaction 2HgO(s) The equilibrium constant,K,for the reaction 2HgO(s)    2Hg(l) + O<sub>2</sub>(g)  Is 1.2 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>30</sup>.Calculate K for the reaction 1/2O<sub>2</sub>(g) + Hg(l)    HgO(s) . A) (<font face= symbol ></font>1.1 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>15 </sup>)  B) 8.3 <font face= symbol ></font> 10<sup>29 </sup> C) 4.2 <font face= symbol ></font> 10<sup>29 </sup> D) 9.1 <font face= symbol ></font> 10<sup>14 </sup> E) 1.1 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>15 </sup> 2Hg(l) + O2(g)
Is 1.2 1030.Calculate K for the reaction
1/2O2(g) + Hg(l) The equilibrium constant,K,for the reaction 2HgO(s)    2Hg(l) + O<sub>2</sub>(g)  Is 1.2 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>30</sup>.Calculate K for the reaction 1/2O<sub>2</sub>(g) + Hg(l)    HgO(s) . A) (<font face= symbol ></font>1.1 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>15 </sup>)  B) 8.3 <font face= symbol ></font> 10<sup>29 </sup> C) 4.2 <font face= symbol ></font> 10<sup>29 </sup> D) 9.1 <font face= symbol ></font> 10<sup>14 </sup> E) 1.1 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>15 </sup> HgO(s) .


Definitions:

Petty Cash

A small amount of cash on hand used for covering minor expenses.

Balance Sheet

A financial statement that summarizes a company's assets, liabilities, and stockholders' equity at a specific point in time, providing a snapshot of its financial condition.

Cash Equivalents

Short-term, highly liquid investments that are readily convertible to known amounts of cash and which are subject to an insignificant risk of changes in value.

Short-Term Investments

Assets that are expected to be converted into cash or sold within one year or the operating cycle, whichever is longer.

Related Questions