Calculate the Standard Reaction Enthalpy for the Reaction A) -935 KJ

question 55

Multiple Choice

Calculate the standard reaction enthalpy for the reaction.
$\begin{array}{ll}\mathrm{N}_{2} \mathrm{H}_{4}(\mathrm{l}) +\mathrm{H}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{NH}_{3}(\mathrm{~g}) \\\text { Given: }\mathrm{N}_{2} \mathrm{H}_{4}(\mathrm{l}) +\mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{N}_{2}(\mathrm{~g}) +2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) & \Delta H^{\circ}=-543 \mathrm{~kJ} \cdot \mathrm{mol}^{-1} \\2 \mathrm{H}_{2}(\mathrm{~g}) +\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) & \Delta H^{\circ}=-484 \mathrm{~kJ} \cdot \mathrm{mol}^{-1} \\\mathrm{~N}_{2}(\mathrm{~g}) +3 \mathrm{H}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{NH}_{3}(\mathrm{~g}) & \Delta H^{\circ}=-92.2 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\end{array}$

• A) -935 kJ.mol^-1
• B) -1119 kJ.mol^-1
• C)-151 kJ.mol^-1
• D) -59 kJ.mol^-1
• E) -243 kJ.mol^-1

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