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Calculate the Lattice Enthalpy of Potassium Chloride Given the Following

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Calculate the lattice enthalpy of potassium chloride given the following enthalpy data.
K(s)K(g)+89 kJmol1 K( g)K+(g)+e+418 kJmol11/2Cl2( g)Cl(g)+122 kJmol1Cl(g)eCl(g)349 kJmol1 K( s)+1/2Cl2( g)KCl(s)437 kJmol1\begin{array} { l l } \mathrm { K } ( \mathrm { s } ) \rightarrow \mathrm { K } ( \mathrm { g } ) & + 89 \mathrm {~kJ} \cdot \mathrm { mol } ^ { - 1 } \\\mathrm {~K} ( \mathrm {~g} ) \rightarrow \mathrm { K } ^ { + } ( \mathrm { g } ) + \mathrm { e } ^ { - } & + 418 \mathrm {~kJ} \cdot \mathrm { mol } ^ { - 1 } \\1 / 2 \mathrm { Cl } _ { 2 } ( \mathrm {~g} ) \rightarrow \mathrm { Cl } ( \mathrm { g } ) & + 122 \mathrm {~kJ} \cdot \mathrm { mol } ^ { - 1 } \\\mathrm { Cl } ( \mathrm { g } ) \mathrm { e } ^ { - } \rightarrow \mathrm { Cl } ^ { - } ( \mathrm { g } ) & - 349 \mathrm {~kJ} \cdot \mathrm { mol } ^ { - 1 } \\\mathrm {~K} ( \mathrm {~s} ) + 1 / 2 \mathrm { Cl } _ { 2 } ( \mathrm {~g} ) \rightarrow \mathrm { KCl } ( \mathrm { s } ) & - 437 \mathrm {~kJ} \cdot \mathrm { mol } ^ { - 1 }\end{array}


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Mean

The average of a set of numbers, calculated by dividing the sum of all values by the number of values.

Median

The middle value in a dataset when ordered from smallest to largest, serving as a measure of central tendency.

Mode

The value that appears most frequently in a data set, a measure of central tendency.

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