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In the Circuit Shown,R1 = 5 Ω\varOmega ,R2 = 10 Ω\varOmega ,And R3 = 15

question 44

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In the circuit shown,R1 = 5 Ω\varOmega ,R2 = 10 Ω\varOmega ,and R3 = 15 Ω\varOmega ,and ε\varepsilon 1 = 10 V,and ε\varepsilon 2 = 15 V.Using Kirchhoff's loop and junction laws,determine the currents I1,I2,and I3 flowing through R1,R2,and R3,respectively,where the direction of each current is as indicated in the figure.  In the circuit shown,R<sub>1</sub> = 5  \varOmega ,R<sub>2</sub> = 10  \varOmega ,and R<sub>3</sub> = 15  \varOmega ,and  \varepsilon <sub>1</sub> = 10 V,and  \varepsilon <sub>2</sub> = 15 V.Using Kirchhoff's loop and junction laws,determine the currents I<sub>1</sub>,I2,and I<sub>3</sub> flowing through R<sub>1</sub>,R<sub>2</sub>,and R<sub>3</sub>,respectively,where the direction of each current is as indicated in the figure.   A) I<sub>1</sub> = 0.636 A,I<sub>2</sub> = 0.545 A,I<sub>3</sub> = 0.091 A B) I<sub>1</sub> = 0.091 A,I<sub>2</sub> = 0.545 A,I<sub>3</sub> = 0.636 A C) I<sub>1</sub> = 1.0 A,I<sub>2</sub> = -1.0 A,I<sub>3</sub> = 2.0 A D) I<sub>1</sub> = 0.5 A,I<sub>2</sub> = 1.5 A,I<sub>3</sub> = 1.0 A


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