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A Thin Glass Rod Is Bent into a Semicircle of Radius

question 14

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A thin glass rod is bent into a semicircle of radius R.A charge + Q is uniformly distributed along the upper half,and a charge -Q is uniformly distributed along the lower half,as shown in the figure.If Q = 10 nC and the electric field E at point P is 5.85 * 104 N/C in -y direction,what is the radius of the semicircle,R? Point P is at the center of the semicircle. A thin glass rod is bent into a semicircle of radius R.A charge + Q is uniformly distributed along the upper half,and a charge -Q is uniformly distributed along the lower half,as shown in the figure.If Q = 10 nC and the electric field E at point P is 5.85 * 10<sup>4</sup> N/C in -y direction,what is the radius of the semicircle,R? Point P is at the center of the semicircle.   A) 10 cm B) 9.0 cm C) 14 cm D) 16 cm E) 12 cm


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