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The Radius of Curvature of a Highway Exit Is R

question 43

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The radius of curvature of a highway exit is r = 68.5 m.The surface of the exit road is horizontal,not banked.(See figure.) If the static friction between the tires and the surface of the road is µs = 0.688,then what is the maximum speed at which the car can exit the highway safely without sliding? (in m/s) The radius of curvature of a highway exit is r = 68.5 m.The surface of the exit road is horizontal,not banked.(See figure.) If the static friction between the tires and the surface of the road is µs = 0.688,then what is the maximum speed at which the car can exit the highway safely without sliding? (in m/s)    A) 1.57 * 10<sup>1</sup> B) 1.84 * 10<sup>1</sup> C) 2.15 * 10<sup>1</sup> D) 2.52 * 10<sup>1</sup> E) 2.94 * 10<sup>1</sup>


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