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question 82

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How many millilitres of 0.200 mol L-1 FeCl3 are needed to react with an excess of Na2S to produce 1.38 g of Fe2S3 if the percent yield for the reaction is 65.0%?
3Na2S(aq) + 2FeCl3(aq) → Fe2S3(s) + 6NaCl(aq)


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