When 150 Mol of CH₄(g)reacts with Excess Cl₂(g)at Constant Pressure According

question 109

Multiple Choice

When 1.50 mol of CH₄(g) reacts with excess Cl₂(g) at constant pressure according to the chemical equation shown below,1062 kJ of heat are released.Calculate the value of ?H for this reaction,as written.
2CH₄(g) + 3Cl₂(g) ? 2CHCl₃(l) + 3H₂(g) $\Delta _ { \mathrm { r } }$ H° = ?

• A)-1420 kJ \(\mathrm { mol } ^ { - 1 }\)
• B)-708 kJ \(\mathrm { mol } ^ { - 1 }\)
• C)+708 kJ \(\mathrm { mol } ^ { - 1 }\)
• D)+1420 kJ \(\mathrm { mol } ^ { - 1 }\)

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