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The Enthalpy Change for Converting 10 2.09Jg1C12.09 \mathrm { Jg } ^ { - 1 } { } ^ { \circ } \mathrm { C } ^ { - 1 }

question 122

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The enthalpy change for converting 10.0 g of ice at -25.0 °C to water at 80.0 °C is ________ kJ.The specific heats of ice,water,and steam are 2.09Jg1C12.09 \mathrm { Jg } ^ { - 1 } { } ^ { \circ } \mathrm { C } ^ { - 1 } 4.18Jg1C14.18 \mathrm { Jg } ^ { - 1 } { } ^ { \circ } \mathrm { C } ^ { - 1 } and 1.84Jg1C11.84 \mathrm { Jg } ^ { - 1 } { } ^ { \circ } \mathrm { C } ^ { - 1 } respectively.For H2\mathrm { H } _ { 2 } O, Δfus H\Delta _ { \text {fus } } H = 6.01 kJ mol-1,and Δvap H=40.67 kJ mol1\Delta _ { \text {vap } } H = 40.67 \mathrm {~kJ} \mathrm {~mol} ^ { - 1 } .


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