The Second-Order Reaction 2 Mn(CO)₅ → Mn₂(CO)₁₀ Has a Rate

question 97

Multiple Choice

The second-order reaction 2 Mn(CO) ₅ → Mn₂(CO) ₁₀ has a rate constant equal to 3.0 × 10⁹ L mol^-1 s^-1 at 25 °C.If the initial concentration of Mn(CO) ₅ is 2.0 × 10^-5 mol L^-1,how long will it take for 90.% of the reactant to disappear?

• A)6.7 × 10^-16 s
• B)7.4 × 10^-15 s
• C)1.5 × 10^-4 s
• D)6.0 × 10³ s